Doxylamine Succinate
Ethanamine,N,N-dimethyl-2-[1-phenyl-1-(2-pyridinyl)ethoxy]-,butanedioate (1:1). 2-[a-[2-(Dimethylamino)ethoxy]-a-methylbenzyl]pyridine succinate (1:1) [562-10-7]. »Doxylamine Succinate contains not less than 98.0percent and not more than 101.0percent of C17H22N2O·C4H6O4,calculated on the dried basis.
Packaging and storage
Preserve in well-closed,light-resistant containers.
Identification
A:
Ultraviolet absorption á197Uñ
Solution:
20µg per mL.
Medium:
0.1Nhydrochloric acid.
Absorptivities at 262nm,calculated on the dried basis,do not differ by more 3.0%.
B:
It meets the requirements under IdentificationOrganic Nitrogenous Bases á181ñ.
C:
Dissolve about 500mg in 5mLof water,and add a slight excess of 6Nammonium hydroxide.Extract the liberated doxylamine with several portions of ether,discard the ether extracts,and evaporate the aqueous solution on a steam bath to dryness.Add 2mLof 3Nhydrochloric acid,and again evaporate on the steam bath to dryness.Cool,add about 10mLof ether,allow to stand for a few minutes,and decant the clear supernatant.Evaporate the ether solution to dryness,and dry the residue at 105
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Melting range,Class Iá741ñ:
between 103
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Loss on drying á731ñ
Dry it in vacuum over phosphorus pentoxide for 5hours:it loses not more than 0.5%of its weight.
Residue on ignition á281ñ:
not more than 0.1%.
Volatile related compounds
Dissolve 650mg in 20mLof 0.1Nhydrochloric acid in a separator.Render the solution alkaline with 2.5Nsodium hydroxide,and immediately extract with four 25-mLportions of ether,filtering each extract through an ether-saturated pledget of cotton.Evaporate the combined ether extracts on a water bath with the aid of a current of air to dryness at a temperature not exceeding 50
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Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Assay
Dissolve about 500mg of Doxylamine Succinate,accurately weighed,in 80mLof glacial acetic acid.Add crystal violet TS,and titrate with 0.1Nperchloric acid VSto an emerald-green endpoint.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 19.42mg of C17H22N2O·C4H6O4.
Auxiliary Information
Staff Liaison:Karen A Russo,Ph.D.,Scientist
Expert Committee:(PA1)Pharmaceutical Analysis 1
USP28NF23Page 702
Phone Number:1-301-816-8379
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