Alanine
»Alanine contains not less than 98.5percent and not more than 101.5percent of C3H7NO2,as L-alanine,calculated on the dried basis.
Packaging and storage
Preserve in tight containers,and store at controlled room temperature.
Identification,Infrared Absorption á197Kñ.
Specific rotation á781Sñ:
between +13.7
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Test solution:
100mg per mL,in 6Nhydrochloric acid.
pHá791ñ:
between 5.5and 7.0in a solution (1in 20).
Loss on drying á731ñ
Dry it at 105
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Residue on ignition á281ñ:
not more than 0.15%.
Chloride á221ñ
A1.0-g portion shows no more chloride than corresponds to 0.70mLof 0.020Nhydrochloric acid (0.05%).
Sulfate á221ñ
A1.0-g portion shows no more sulfate than corresponds to 0.30mLof 0.020Nsulfuric acid (0.03%).
Iron á241ñ:
0.003%.
Heavy metals,Method Iá231ñ:
0.0015%.
Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Dissolve an accurately weighed quantity of Alanine in water to obtain a solution having a concentration of 10mg per mL.Apply 5µL.
Standard solution
Dissolve an accurately weighed quantity of USPL-Alanine RSin water to obtain a solution having a known concentration of about 0.05mg per mL.Apply 5µL.[NOTEThis solution has a concentration equivalent to about 0.5%of that of the Test solution.]
System suitability solution
Prepare a solution in water containing 0.4mg each of USPL-Alanine RSand USP Glycine RSper mL.Apply 5µL.
Spray reagent
Dissolve 0.2g of ninhydrin in 100mLof a mixture of butyl alcohol and 2Nacetic acid (95:5).
Developing solvent system
Prepare a mixture of butyl alcohol,glacial acetic acid,and water (60:20:20).
Procedure
Proceed as directed forThin-Layer Chromatography underChromatography á621ñ.After air-drying the plate,repeat the development process.After air-drying a second time,spray withSpray reagent,and heat between 100
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Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Assay
Transfer about 80mg of Alanine,accurately weighed,to a 125-mLflask,dissolve in a mixture of 3mLof formic acid and 50mLof glacial acetic acid,and titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 8.909mg of C3H7NO2.
Auxiliary Information
Staff Liaison:Lawrence Evans,III,Ph.D.,Scientist
Expert Committee:(DSN)Dietary Supplements:Non-Botanicals
USP28NF23Page 54
Pharmacopeial Forum:Volume No.27(5)Page 2973
Phone Number:1-301-816-8389
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