In some assays,the potential responses can be assembled into homogeneous sets in advance of treatment.The differences between sets are later segregated,so that they do not affect adversely either the computed potency or its confidence interval.One unit within each set,picked at random,receives each treatment.Examples of randomized sets are the cleared areas on a single plate in the plate assay of an antibiotic,and four successive paired readings in the same rat in the Vasopressin Injection assay.Sets of two occur where each test animal is used twice,as in the assays of Tubocurarine Chloride Injection and Insulin Injection.In these cases,neither the average differences between individuals nor the order of treatment can bias the potency or precision.In the microbial assays for vitamin B12activity and for calcium pantothenate,replicate tubes are assigned to two or more separate,complete sets,preferably with the tubes arranged at random within each set.This restricts the variation due to position or order within a set to the differences within each complete replicate.

1.The first criterion is based upon the variation within a single group of supposedly equivalent responses.On the average,it will reject a valid observation once in 25or once in 50trials,provided that relatively few,if any,responses within the group are identical.Beginning with the supposedly erratic value or outlier,designate the responses in order of magnitude from y1to yN,where Nis the number of observations in the group.Compute the relative gap G1=(y2-y1)/(yN-y1)when N=3to 7,G2=(y3-y1)/(yN-1-y1)when N=8to 13,or G3=(y3-y1)/(yN-2-y1)when N=14to 24.If G1,G2,or G3exceeds the critical value in Table 1for the observed N,there is a statistical basis for omitting the outlier.

Table 1

This criterion is applicable also in a microbial assay where each treatment is represented by a transmittance in each of two separate complete sets.Subtract each transmittance in the first set from its paired value in the second set,and record each difference with its sign,either plus or minus.Beginning with the most divergent difference,designate the Ndifferences in order of magnitude from y1to yNand compute the relative gap G1,G2,or G3.If this exceeds its critical value in Table 1,one of the two transmittances giving the aberrant difference is suspect and may be identified on inspection or by comparison with its expectation (see next column).Repeat the process with the remaining differences if an outlier is suspected in a second pair.

2.The second criterion compares the ranges from a series of k=2or more groups.Different groups may receive different treatments,but all fresponses within each group represent the same treatment.Compute the range from each group by subtracting the smallest response from the largest within each of the kgroups.Divide the largest of the kranges by the sum of all the ranges in the series.Refer this ratio R*to Table 2.If kis not larger than 10,use the tabular values in the upper part of Table 2;if kis larger than 10,multiply R*by (k+2)and interpolate,if necessary,between the tabular values in the lower part of Table 2.If R*exceeds the tabular or interpolated value,the group with the largest range is suspect and inspection of its components will usually identify the observation,which is then assumed to be aberrant or an outlier.The process may be repeated with the remaining ranges if an outlier is suspected in a second group.

Table 2

1.Reduce the number of observations in the larger groups until the number of responses is the same for each treatment.If animals have been assigned at random to each treatment group,either omit one or more responses,selected at random,from each larger group,or subtract the mean of each larger group from its initial total as often as may be necessary.The latter technique is preferred when extra animals have been assigned deliberately to the Standard.When the assay consists of randomized sets,retain only the complete sets.

2.Alternatively,an occasional smaller group may be brought up to size when the number of missing responses is not more than one in any one treatment or 10%in the entire assay.Estimate a replacement for each missing value by either method aor method b.One degree of freedom (n)is lost from the error variance s2for each replacement by either method,except in a microbial assay where each response is based on the sum of two or more transmittances and only one transmittance is replaced.

(a)If animals have been assigned to treatments at random,add the mean of the remaining responses in the incomplete group to their total.In a microbial assay,when one of two transmittances is missing for a given treatment,add the mean difference between sets,computed from all complete pairs,to the remaining transmittance to obtain the replacement.

(b)If the assay consists of randomized sets,replace the missing value by

where fis the number of sets,kis the number of treatments or doses,and Tr¢,Tt¢,and T¢are the incomplete totals for the randomized set,treatment,and assay from which an observation is missing.

If the assay consists of n¢Latin squares with krows in common,replace a missing value by

where n¢is the number of Latin squares with krows in common,kis the number of treatments or doses,and Tc¢,Tr¢,Tt¢,and T¢are respectively the incomplete totals for the column,row,treatment,and assay from which an observation is missing.

If more than one value is missing,substitute the treatment mean temporarily in all but one of the empty places,and compute y¢for the other by Equation 1.Replace each of the initial substitutions in turn by Equation 1,and repeat the process in successive approximations until a stable y¢is obtained for each missing observation.