Proparacaine Hydrochloride
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C16H26N2O3·HCl 330.85

Benzoic acid,3-amino-4-propoxy-,2-(diethylamino)ethyl ester,monohydrochloride.
2-(Diethylamino)ethyl 3-amino-4-propoxybenzoate monohydrochloride [5875-06-9].
»Proparacaine Hydrochloride contains not less than 97.0percent and not more than 103.0percent of C16H26N2O3·HCl,calculated on the dried basis.
Packaging and storage— Preserve in well-closed containers.
Identification—
A: It meets the requirements under Identification—Organic Nitrogenous Bases á181ñ.
B: Dissolve 50mg,accurately weighed,in water to make 250.0mL,and mix.Pipet 10mLof this solution into a 100-mLvolumetric flask,add 2mLof 10percent,pH6.0phosphate buffer (see Buffer Solutionsin the section Reagents,Indicators,and Solutions),add water to volume,and mix:the UVabsorption spectrum of the solution exhibits maxima and minima at the same wavelengths as that of a similar solution of USP Proparacaine Hydrochloride RS,concomitantly measured,and the respective absorptivities,calculated on the dried basis,at the wavelength of maximum absorbance at about 310nm do not differ by more than 3.0%.
C: Asolution (1in 50)responds to the tests for Chloride á191ñ,the procedure for alkaloidal hydrochlorides being used.
Melting range á741ñ: between 178and 185,but the range between beginning and end of melting does not exceed 2.
Loss on drying á731ñ Dry it at 105for 3hours:it loses not more than 0.5%of its weight.
Residue on ignition á281ñ: not more than 0.15%.
Ordinary impurities á466ñ
Test solution: methanol.
Standard solution: methanol.
Eluant: a mixture of butyl alcohol,water,and glacial acetic acid (5:3:1).
Visualization: 1;17.
Assay— Place 250mg of Proparacaine Hydrochloride,accurately weighed,in a 250-mLconical flask,add 80mLof a 1in 20solution of acetic anhydride in glacial acetic acid,and heat on a steam bath for 10minutes.Cool to room temperature,add 10mLof mercuric acetate TSand 1or 2drops of crystal violet TS,and titrate with 0.1Nperchloric acid VSto a blue-green endpoint.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 33.09mg of C16H26N2O3·HCl.
Auxiliary Information— Staff Liaison:Karen A Russo,Ph.D.,Scientist
Expert Committee:(PA1)Pharmaceutical Analysis 1
USP28–NF23Page 1646
Phone Number:1-301-816-8379