Arginine
»Arginine contains not less than 98.5percent and not more than 101.5percent of C6H14N4O2,as L-arginine,calculated on the dried basis.
Packaging and storage
Preserve in well-closed containers.
Identification,
Infrared Absorption á197Kñ.
Specific rotation á781Sñ:
between +26.3
![]() ![]()
Test solution:
80mg per mL,in 6Nhydrochloric acid.
Loss on drying á731ñ
Dry it at 105
![]()
Residue on ignition á281ñ:
not more than 0.3%.
Chloride á221ñ
A1.0-g portion shows no more chloride than corresponds to 0.70mLof 0.020Nhydrochloric acid (0.05%).
Sulfate á221ñ
A1.0-g portion shows no more sulfate than corresponds to 0.30mLof 0.020Nsulfuric acid (0.03%).
Iron á241ñ:
0.003%.
Heavy metals,Method Iá231ñ:
0.0015%.
Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Dissolve an accurately weighed quantity of Arginine in 2Nhydrochloric acid to obtain a solution having a concentration of 10mg per mL.Apply 5µL.
Standard solution
Dissolve an accurately weighed quantity of USPL-Arginine RSin 0.1Nhydrochloric acid to obtain a solution having a known concentration of about 0.05mg per mL.Apply 5µL.[NOTEThis solution has a concentration equivalent to about 0.5%of that of the Test solution.]
System suitability solution
Prepare a solution in 0.1Nhydrochloric acid containing 0.4mg each of USPL-Arginine RSand USPL-Lysine Hydrochloride RSper mL.Apply 5µL.
Spray reagent
Dissolve 0.2g of ninhydrin in 100mLof a mixture of butyl alcohol and 2Nacetic acid (95:5).
Developing solvent system
Prepare a mixture of isopropyl alcohol and ammonium hydroxide (70:30).
Procedure
Proceed as directed for Thin-Layer Chromatographyunder Chromatography á621ñ.Dry the plate between 100
![]() ![]() ![]() ![]()
Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Solvent
Use water.
Assay
Transfer about 80mg of Arginine,accurately weighed,to a 125-mLflask,dissolve in a mixture of 3mLof formic acid and 50mLof glacial acetic acid,and titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 8.710mg of C6H14N4O2.
Auxiliary Information
Staff Liaison:Lawrence Evans,III,Ph.D.,Scientist
Expert Committee:(DSN)Dietary Supplements:Non-Botanicals
USP28NF23Page 175
Phone Number:1-301-816-8389
|