Lysine Acetate
»Lysine Acetate contains not less than 98.0percent and not more than 102.0percent of C6H14N2O2·C2H4O2,as L-lysine acetate,calculated on the dried basis.
Packaging and storage
Preserve in well-closed containers.
Identification,Infrared Absorption á197Kñ.
Specific rotation á781Sñ:
between +8.4
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Test solution:
100mg per mL,in water.
Loss on drying á731ñ
Dry it at 80
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Residue on ignition á281ñ:
not more than 0.4%.
Chloride á221ñ
A0.73-g portion shows no more chloride than corresponds to 0.50mLof 0.020Nhydrochloric acid (0.05%).
Sulfate á221ñ
A0.33-g portion shows no more sulfate than corresponds to 0.10mLof 0.020Nsulfuric acid (0.03%).
Iron á241ñ:
0.003%.
Heavy metals,Method Iá231ñ:
0.0015%.
Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Dissolve an accurately weighed quantity of Lysine Acetate in water to obtain a solution having a concentration of 10mg per mL.Apply 5µL.
Standard solution
Dissolve an accurately weighed quantity of USP L-Lysine Acetate RSin water to obtain a solution having a known concentration of about 0.05mg per mL.Apply 5µL.[NOTEThis solution has a concentration equivalent to about 0.5%of that of the Test solution.]
System suitability solution
Prepare a solution in water containing 0.4mg each of USP L-Lysine Acetate RSand USP Arginine Hydrochloride RSper mL.Apply 5µL.
Spray reagent
Dissolve 0.2g of ninhydrin in 100mLof a mixture of butyl alcohol and 2Nacetic acid (95:5).
Developing solvent system
Prepare a mixture of isopropyl alcohol and ammonium hydroxide (70:30).
Procedure
Proceed as directed for Thin-Layer Chromatographyunder Chromatography á621ñ.Dry the plate between 100
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Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Assay
Transfer about 100mg of Lysine Acetate,accurately weighed,to a 125-mLflask,dissolve in a mixture of 3mLof formic acid and 50mLof glacial acetic acid,and titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically.Perform a blank determination and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 10.31mg of C6H14N2O2·C2H4O2.
Auxiliary Information
Staff Liaison:Lawrence Evans,III,Ph.D.,Scientist
Expert Committee:(DSN)Dietary Supplements:Non-Botanicals
USP28NF23Page 1159
Phone Number:1-301-816-8389
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