Dipyridamole
Ethanol,2,2¢,2¢¢,2¢¢¢-[4,8-di-1-piperidinylpyrimido[5,4-d]pyrimidine-2,6-diyl)dinitrilo]tetrakis-. 2,2¢,2¢¢,2¢¢¢-[4,8-Dipiperidinopyrimido[5,4-d]pyrimidine-2,6-diyl)dinitrilo]tetraethanol [58-32-2]. »Dipyridamole contains not less than 98.0percent and not more than 102.0percent of C24H40N8O4,calculated on the dried basis.
Packaging and storage
Preserve in tight,light-resistant containers.Store at room temperature.
Identification,Infrared Absorption á197Kñ.
Melting range á741ñ:
between 162and 168,but the range between beginning and end of melting does not exceed 2.
Loss on drying á731ñ
Dry it at 105for 3hours:it loses not more than 0.2%of its weight.
Chloride
Dissolve 500mg in 5mLof alcohol and 2mLof 2Nnitric acid,and add 1mLof silver nitrate TS:no turbidity or precipitate is produced.
Residue on ignition á281ñ:
not more than 0.1%.
Heavy metals,Method IIá231ñ:
0.001%.
Organic volatile impurities,Method IVá467ñ:
meets the requirements.
Chromatographic purity
Test preparation A
Prepare a solution of Dipyridamole in methanol having a known concentration of 1mg per mL.
Test preparation B
Dilute 1.0mLof Test preparation Awith methanol to 100mL,and mix.
Procedure
Inject 10µLof Test preparation Binto the chromatograph by means of a sampling valve,adjusting the operating parameters so that the response of the main peak (retention time about 6.5minutes)obtained is about 5%full scale.Inject 10µLof Test preparation A,and run the chromatograph for 10minutes:the sum of responses of all secondary peaks obtained from Test preparation Ais not greater than the response of the main peak obtained from Test preparation B(1.0%).
Assay
Transfer about 450mg of Dipyridamole,accurately weighed,to a 250-mLbeaker,and dissolve in 50mLof glacial acetic acid.Stir for 30minutes.Add 75mLof acetone,and stir for an additional 15minutes.Titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically,using a glass electrode and a silver-silver chloride reference electrode system.Perform a blank titration,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 50.46mg of C24H40N8O4.
Auxiliary Information
Staff Liaison:Andrzej Wilk,Ph.D.,Senior Scientific Associate
Expert Committee:(PA5)Pharmaceutical Analysis 5
USP28NF23Page 673
Pharmacopeial Forum:Volume No.29(5)Page 1467
Phone Number:1-301-816-8305
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